Math Problem Statement

The width of a rectangle is 6 inches, and the diagonal length of the rectangle is 15 inches.

Which measurement is closest to the length of the rectangle? A.9 inches B. 13.7 inches

C.21 inches D.16.2 inches

Solution

To find the length of the rectangle, we can use the Pythagorean Theorem. The Pythagorean Theorem relates the width ww, length ll, and diagonal dd of a rectangle as follows:

d2=w2+l2d^2 = w^2 + l^2

Where:

  • w=6inchesw = 6 \, \text{inches}
  • d=15inchesd = 15 \, \text{inches}
  • ll is the length of the rectangle (which we need to find).

Plugging in the values:

152=62+l215^2 = 6^2 + l^2 225=36+l2225 = 36 + l^2 22536=l2225 - 36 = l^2 l2=189l^2 = 189 l=18913.75inchesl = \sqrt{189} \approx 13.75 \, \text{inches}

Thus, the length of the rectangle is approximately 13.7 inches.

The closest answer is B. 13.7 inches.

Would you like further details or have any questions?

Here are 5 related questions:

  1. How does the Pythagorean theorem apply to different shapes?
  2. What happens if the rectangle were a square?
  3. Can the length ever be larger than the diagonal?
  4. How would the formula change for a 3D object, such as a cuboid?
  5. How would the solution change if the width was increased?

Tip: When dealing with right triangles, the diagonal (hypotenuse) is always the longest side.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Right Triangles

Formulas

Pythagorean Theorem: d^2 = w^2 + l^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-10