The image asks for the Least Common Multiple (LCM) of the numbers $10$, $20$, and $25$.

Step-by-step solution:

1. Prime factorization of the numbers:

   • $10 = 2 \cdot 5$
   • $20 = 2^2 \cdot 5$
   • $25 = 5^2$

2. Find the highest powers of all the prime factors:

   • $2$: The highest power is $2^2$ (from $20$).
   • $5$: The highest power is $5^2$ (from $25$).

3. Multiply the highest powers together: $\text{LCM} = 2^2 \cdot 5^2 = 4 \cdot 25 = 100$

Final Answer:

The LCM of $10$, $20$, and $25$ is 100.

Let me know if you would like further explanation or examples!

Related Questions:

1. What is the GCD (Greatest Common Divisor) of $10$, $20$, and $25$?
2. How is LCM useful in solving fraction problems?
3. Can LCM be smaller than any of the numbers in the set?
4. How would you calculate the LCM of three numbers using the division method?
5. What is the LCM of $15$, $30$, and $50$?

Tip:

Always use the prime factorization method for finding the LCM when the numbers are not too large—it ensures accuracy!