Math Problem Statement

The straight line l has the equation y = k(2x - 1), where k is a constant. The curve C has the equation y = x^2 + 2x + 11. Find the set of values of k for which l does not cross or touch C.

Solution

We are given the following two equations:

  1. The straight line ll: y=k(2x1)y = k(2x - 1) where kk is a constant.

  2. The curve CC: y=x2+2x+11y = x^2 + 2x + 11

We are tasked with finding the set of values of kk for which the line ll does not cross or touch the curve CC. This means we need to determine when the system of equations has no real solutions.

Step 1: Equating the two expressions for yy

To find when the line and the curve do not intersect, we equate the two equations for yy: k(2x1)=x2+2x+11k(2x - 1) = x^2 + 2x + 11

Step 2: Rearrange the equation into a quadratic form

Expand the left-hand side: 2kxk=x2+2x+112kx - k = x^2 + 2x + 11

Now, bring all terms to one side of the equation: x2+(22k)x+(11+k)=0x^2 + (2 - 2k)x + (11 + k) = 0 This is now a quadratic equation of the form: Ax2+Bx+C=0Ax^2 + Bx + C = 0 where A=1A = 1, B=22kB = 2 - 2k, and C=11+kC = 11 + k.

Step 3: Use the discriminant

For the line and the curve not to intersect, the quadratic equation must have no real solutions. This happens when the discriminant Δ\Delta is less than 0. The discriminant for a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by: Δ=B24AC\Delta = B^2 - 4AC Substitute the values for AA, BB, and CC: Δ=(22k)24(1)(11+k)\Delta = (2 - 2k)^2 - 4(1)(11 + k)

Simplify: Δ=(48k+4k2)4(11+k)\Delta = (4 - 8k + 4k^2) - 4(11 + k) Δ=4k28k+4444k\Delta = 4k^2 - 8k + 4 - 44 - 4k Δ=4k212k40\Delta = 4k^2 - 12k - 40

Step 4: Solve Δ<0\Delta < 0

For the line not to touch the curve, we require: 4k212k40<04k^2 - 12k - 40 < 0

Divide through by 4 to simplify: k23k10<0k^2 - 3k - 10 < 0

Step 5: Solve the quadratic inequality

We first solve the equality k23k10=0k^2 - 3k - 10 = 0 using the quadratic formula: k=(3)±(3)24(1)(10)2(1)k = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(1)(-10)}}{2(1)} k=3±9+402k = \frac{3 \pm \sqrt{9 + 40}}{2} k=3±492k = \frac{3 \pm \sqrt{49}}{2} k=3±72k = \frac{3 \pm 7}{2}

Thus, the solutions are: k=3+72=5ork=372=2k = \frac{3 + 7}{2} = 5 \quad \text{or} \quad k = \frac{3 - 7}{2} = -2

Step 6: Interpret the inequality

The quadratic inequality k23k10<0k^2 - 3k - 10 < 0 holds between the roots k=2k = -2 and k=5k = 5. Therefore, the set of values for which the line does not intersect the curve is: 2<k<5-2 < k < 5

Final Answer:

The line does not cross or touch the curve for k(2,5)k \in (-2, 5).


Would you like a detailed explanation of any step?

Here are 5 questions to extend your understanding:

  1. Why is the discriminant used to determine whether the line intersects the curve?
  2. How would the solution change if we were asked for the values of kk where the line does intersect the curve?
  3. What is the geometric interpretation of solving k23k10<0k^2 - 3k - 10 < 0?
  4. How could we use a graphical method to solve this problem?
  5. What would happen to the solution if the curve CC had different coefficients?

Tip: Always check the discriminant when solving for intersection conditions between a line and a curve, as it quickly tells you whether real solutions exist.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Discriminant

Formulas

y = k(2x - 1)
y = x^2 + 2x + 11
Quadratic Discriminant: Δ = B^2 - 4AC

Theorems

Quadratic formula
Discriminant condition for no real solutions

Suitable Grade Level

Grades 10-12