Math Problem Statement

Find the value of k if, on the day when 200 books were printed, the average cost was $9 per book. The average cost function is c(x) = (5.5x + k) / x, where x is the number of books printed and k is a constant.

Solution

We are given that the average cost c(x)c(x) for printing a book is represented by the function:

c(x)=5.5x+kxc(x) = \frac{5.5x + k}{x}

where xx is the number of books printed, and kk is a constant. We are asked to find the value of kk if the average cost per book is $9 when 200 books are printed (i.e., x=200x = 200).

Step-by-Step Solution:

  1. Plug in the given values:
    • c(x)=9c(x) = 9 (the average cost),
    • x=200x = 200 (the number of books).

9=5.5(200)+k2009 = \frac{5.5(200) + k}{200}

  1. Simplify the equation:

9=1100+k2009 = \frac{1100 + k}{200}

  1. Multiply both sides by 200 to eliminate the denominator:

9×200=1100+k9 \times 200 = 1100 + k

1800=1100+k1800 = 1100 + k

  1. Solve for kk:

k=18001100k = 1800 - 1100

k=700k = 700

Thus, the value of kk is 700.

Would you like any further details on this solution?

Here are 5 related questions to expand on this topic:

  1. How would the average cost change if the number of books printed was 500 instead of 200?
  2. What is the minimum possible average cost as xx increases?
  3. How would you interpret the constant kk in the context of this cost function?
  4. If the cost per book must remain under $8, what is the minimum number of books that need to be printed?
  5. How would the equation change if the variable cost per book (currently 5.5) increased by 10%?

Tip: When solving problems like these, always remember to check the units and ensure your calculations align with the context of the problem (e.g., costs per book).

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

c(x) = (5.5x + k) / x

Theorems

Solving for unknown constants in linear equations

Suitable Grade Level

Grades 9-12