Let's solve the problem step by step. The question asks to find the point of intersection of two straight lines for each given pair of equations. We will go through each pair of equations:

a) $y = 2x - 1$ and $y = 3x - 3$

To find the point of intersection, set the two equations equal to each other:

$2x - 1 = 3x - 3$

Solving for $x$:

$-1 + 3 = 3x - 2x$

$x = 2$

Substitute $x = 2$ back into one of the original equations, say $y = 2x - 1$:

$y = 2(2) - 1 = 4 - 1 = 3$

So, the point of intersection is $(2, 3)$.

b) $x + y = 16$ and $x + 2y = 10$

We can solve this system by substitution or elimination. Let's use the elimination method. Subtract the second equation from the first:

$(x + y) - (x + 2y) = 16 - 10$

$-x + y = 6$

This simplifies