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Let's solve the problem step by step. The question asks to find the point of intersection of two straight lines for each given pair of equations. We will go through each pair of equations:

### a) \( y = 2x - 1 \) and \( y = 3x - 3 \)
To find the point of intersection, set the two equations equal to each other:

\[
2x - 1 = 3x - 3
\]

Solving for \(x\):

\[
-1 + 3 = 3x - 2x
\]

\[
x = 2
\]

Substitute \(x = 2\) back into one of the original equations, say \(y = 2x - 1\):

\[
y = 2(2) - 1 = 4 - 1 = 3
\]

So, the point of intersection is \( (2, 3) \).

### b) \( x + y = 16 \) and \( x + 2y = 10 \)
We can solve this system by substitution or elimination. Let's use the elimination method. Subtract the second equation from the first:

\[
(x + y) - (x + 2y) = 16 - 10
\]

\[
-x + y = 6
\]

This simplifies

Find the point of intersection of two straight lines in each of the following pairs of equations: a) y = 2x - 1 and y = 3x - 3, b) x + y = 16 and x + 2y = 10, c) 2y = x - 5 and y = -2x + 5, d) 3y = 6 - 4x and 6y = x - 12

This tutorial explains how to find the intersection point of two straight lines using system of equations. Learn key algebraic concepts such as substitution and elimination methods with step-by-step solutions. Suitable for Grades 8-10.

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