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The problem provides that \( x + y = 220^\circ \), and we are asked to find the value of \( n \) in the triangle.

Here's the step-by-step process:

1. **Understanding the Triangle**: The angles \( x \) and \( y \) are external angles at the base of the triangle, and \( n \) is the interior angle at the apex of the triangle.

2. **Exterior Angles Theorem**: The exterior angle of a triangle is equal to the sum of the two opposite interior angles. For this diagram:
   - \( x \) is the exterior angle at the base, and it equals \( n + y \) (the sum of the two opposite interior angles).

3. **Equation for \( n \)**:
   - From the given, \( x + y = 220^\circ \), so the sum of both exterior angles is 220°.
   - In any triangle, the sum of interior angles is always 180°:
     \[
     n + (x + y) = 180^\circ
     \]

4. **Solving for \( n \)**:
   - You now have the equation to solve for \( n \).

Would you like the full detailed calculation?

In the diagram, the value of x + y = 220°. Find the value of n.

Learn how to find the value of an internal angle n in a triangle where the sum of two external angles x and y is given as 220°. This problem explores the Exterior Angle Theorem and the sum of angles in a triangle. Suitable for students in Grades 8-10.

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