https://file.aiquickdraw.com/mathbot/file/1726403788571fih4eqvo.jpg

The problem in the image states:

**The population of a town increased by 35% between 2010 and 2015. In 2015 the population was 9720. What was the population in 2010?**

### Solution:
Let the population in 2010 be \( P_{2010} \).

Since the population increased by 35%, the population in 2015 would be:
\[
P_{2015} = P_{2010} + 0.35 \times P_{2010} = 1.35 \times P_{2010}
\]

We know that the population in 2015 was 9720, so:
\[
1.35 \times P_{2010} = 9720
\]

To find \( P_{2010} \), divide both sides by 1.35:
\[
P_{2010} = \frac{9720}{1.35} = 7200
\]

### Answer:
The population in 2010 was 7200.

---

Would you like more details or have any other questions? Here are 5 related questions for practice:

1. If the population increased by 50% instead of 35%, what would have been the population in 2010?
2. How would the population have changed if it decreased by 15% instead of increasing by 35%?
3. If the population in 2015 was 10,800, what would the population in 2010 have been with the same growth rate?
4. What would the percentage increase be if the population in 2010 was 8000 and in 2015 it became 9720?
5. If the town's population continued to grow by 35% every 5 years, what would the population be in 2020?

**Tip:** To solve similar problems, always express percentage changes as decimal multipliers (e.g., 35% increase as 1.35).

The population of a town increased by 35% between 2010 and 2015. In 2015 the population was 9720. What was the population in 2010?

Learn how to calculate the initial population in 2010 given a 35% population increase between 2010 and 2015. The population in 2015 was 9720, and this problem uses basic algebra and percentage concepts to find the solution. Suitable for Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation