Math Problem Statement

determine the equation of the horizontal asymptope of the graph og the function x-6/2x+1

Solution

To determine the equation of the horizontal asymptote for the function f(x)=x62x+1f(x) = \frac{x - 6}{2x + 1}, follow these steps:

Step 1: Identify the degrees of the numerator and denominator.

  • The numerator x6x - 6 has a degree of 1 (since xx is to the power of 1).
  • The denominator 2x+12x + 1 also has a degree of 1.

Step 2: Compare the degrees of the numerator and denominator.

  • When the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is given by the ratio of the leading coefficients.

Step 3: Find the leading coefficients.

  • The leading coefficient of the numerator (the coefficient of xx) is 1.
  • The leading coefficient of the denominator is 2.

Step 4: Determine the horizontal asymptote.

  • The horizontal asymptote is y=12y = \frac{1}{2}.

So, the equation of the horizontal asymptote is y=12y = \frac{1}{2}.

Would you like more details or have any questions?


Here are 5 related questions to deepen your understanding:

  1. What is the vertical asymptote of the function f(x)=x62x+1f(x) = \frac{x - 6}{2x + 1}?
  2. How would you find the x-intercept of the function f(x)=x62x+1f(x) = \frac{x - 6}{2x + 1}?
  3. What happens to the horizontal asymptote if the degrees of the numerator and denominator are different?
  4. Can a rational function have more than one horizontal asymptote? Why or why not?
  5. How does the horizontal asymptote affect the behavior of the function as xx approaches infinity?

Tip: Always check the degrees of the numerator and denominator when analyzing horizontal asymptotes in rational functions.

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Math Problem Analysis

Mathematical Concepts

Rational Functions
Horizontal Asymptotes

Formulas

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Theorems

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Suitable Grade Level

High School