Math Problem Statement

What is the gradient of the straight line shown below? Give your answer as an integer or as a fraction in its simplest form.

Solution

To find the gradient (or slope) of the straight line shown in the graph, we need to determine the change in yy (vertical change) over the change in xx (horizontal change).

The formula for the gradient is:

Gradient=change in ychange in x=ΔyΔx\text{Gradient} = \frac{\text{change in } y}{\text{change in } x} = \frac{\Delta y}{\Delta x}

From the image, let's identify two points where the line crosses the grid:

  • The line passes through the point (0,6)(0, 6) on the y-axis.
  • It also passes through the point (3,0)(3, 0) on the x-axis.

Using these two points:

  • The change in yy is 60=66 - 0 = 6.
  • The change in xx is 03=30 - 3 = -3.

Now, calculate the gradient:

Gradient=63=2\text{Gradient} = \frac{6}{-3} = -2

Thus, the gradient of the straight line is 2-2.

Would you like further explanation on this? Here are five follow-up questions:

  1. How is the gradient of a line related to its steepness?
  2. Can the gradient of a horizontal line be anything other than zero?
  3. What does a positive gradient signify compared to a negative gradient?
  4. How would you find the gradient if only one point on the line was given?
  5. Can two lines have the same gradient but never intersect?

Tip: When finding the gradient of a line, always remember that a negative gradient means the line is sloping downwards from left to right.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Coordinate Geometry

Formulas

Gradient = (Change in y) / (Change in x)
m = (y2 - y1) / (x2 - x1)

Theorems

Gradient Formula

Suitable Grade Level

Grade 7-9