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The equation provided is in the slope-intercept form \( y = mx + c \), where:

- \( m \) represents the gradient (or slope) of the line.
- \( c \) represents the y-intercept.

In the equation \( y = 11x + 8 \), the coefficient of \( x \) is 11. Therefore, the gradient of the line is:

\[
\text{Gradient} = 11
\]

Would you like further details or have any questions?

Here are five related questions to expand on this topic:
1. How would the graph of the line change if the gradient were negative?
2. What is the y-intercept of the line, and how is it interpreted?
3. How can you find the equation of a line given two points on it?
4. How would you determine the gradient of a line parallel to this one?
5. How would you find the x-intercept of the line given the equation?

**Tip:** In linear equations, the gradient tells you how steep the line is. A larger gradient means a steeper slope.

The equation of a line is y = 11x + 8. What is the gradient of the line?

Understand how to find the gradient of the line given by y = 11x + 8. This problem explores the concepts of linear equations and slope-intercept form, suitable for students in Grades 8-10. Learn how the coefficient of x determines the gradient of the line.

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