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To find \( g(-1) \), we are given that:

\[
g(x) = 5f(x) - 1
\]

From the table, when \( x = -1 \), the value of \( f(x) = 12 \).

Substitute \( f(-1) = 12 \) into the expression for \( g(x) \):

\[
g(-1) = 5f(-1) - 1 = 5(12) - 1 = 60 - 1 = 59
\]

Thus, \( g(-1) = 59 \).

Would you like more details or have any questions?

Here are some related questions for practice:
1. What is \( g(0) \) given the same function \( g(x) = 5f(x) - 1 \)?
2. How would you find \( g(2) \)?
3. Can you generalize how \( g(x) \) behaves based on the table of values for \( f(x) \)?
4. If \( h(x) = 2f(x) + 3 \), what is \( h(-1) \)?
5. What is the general pattern of changes in \( f(x) \) and how does it affect \( g(x) \)?

**Tip**: When substituting into a function, make sure you carefully match the value of the input from the table with the correct output!

Let g(x) = 5f(x) - 1, find g(-1) using the table of values for f(x).

Learn how to find g(-1) using the function g(x) = 5f(x) - 1 and the table of values for f(x). The solution involves substituting the value of f(-1) from the table and applying the formula. Suitable for students in Grades 9-12.

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