Math Problem Statement

Let g(x) = 5f(x) - 1, find g(-1) using the table of values for f(x).

Solution

To find g(1)g(-1), we are given that:

g(x)=5f(x)1g(x) = 5f(x) - 1

From the table, when x=1x = -1, the value of f(x)=12f(x) = 12.

Substitute f(1)=12f(-1) = 12 into the expression for g(x)g(x):

g(1)=5f(1)1=5(12)1=601=59g(-1) = 5f(-1) - 1 = 5(12) - 1 = 60 - 1 = 59

Thus, g(1)=59g(-1) = 59.

Would you like more details or have any questions?

Here are some related questions for practice:

  1. What is g(0)g(0) given the same function g(x)=5f(x)1g(x) = 5f(x) - 1?
  2. How would you find g(2)g(2)?
  3. Can you generalize how g(x)g(x) behaves based on the table of values for f(x)f(x)?
  4. If h(x)=2f(x)+3h(x) = 2f(x) + 3, what is h(1)h(-1)?
  5. What is the general pattern of changes in f(x)f(x) and how does it affect g(x)g(x)?

Tip: When substituting into a function, make sure you carefully match the value of the input from the table with the correct output!

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Math Problem Analysis

Mathematical Concepts

Algebra
Functions

Formulas

g(x) = 5f(x) - 1

Theorems

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Suitable Grade Level

Grades 9-12