Math Problem Statement
Find a list of four distinct vectors in π ^3 whose span equals {(π₯, π¦, π§) β π ^3 βΆ π₯ + π¦ + π§ = 0}.
Solution
To find a list of four distinct vectors in whose span equals the subspace , let's break down the problem step by step.
1. Identify the Subspace:
The subspace consists of all vectors in where the sum of the components is zero. This is a plane in , meaning it's a two-dimensional subspace of .
2. Determine the Dimension:
The equation imposes one linear constraint on the vectors in , so the dimension of this subspace is .
3. Find a Basis:
To find vectors that span this subspace, we need to find two linearly independent vectors and that satisfy the equation . These vectors will form a basis for the subspace.
Two possible vectors could be:
These vectors are linearly independent, and any vector in the subspace can be written as a linear combination of these two vectors.
4. Find Four Distinct Vectors:
Although the dimension of the subspace is 2, we can construct four distinct vectors by choosing appropriate linear combinations. For instance:
5. Verification:
The set of vectors spans the entire subspace since any vector in the subspace can be written as a linear combination of and , and therefore also in terms of and .
Final List of Vectors:
These four distinct vectors span the subspace .
Would you like any details or have any questions?
Here are 5 related questions:
- How can we verify if a set of vectors spans a subspace?
- What does it mean for vectors to be linearly independent?
- How do we determine the dimension of a subspace?
- What is the geometric interpretation of a plane in ?
- How can we find the orthogonal complement of a subspace?
Tip: When finding a spanning set for a subspace, it's helpful to start by determining the dimension of the subspace and finding a basis, which is the smallest set of vectors needed to span the space.
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Math Problem Analysis
Mathematical Concepts
Linear Algebra
Vector Spaces
Subspaces
Formulas
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Theorems
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Suitable Grade Level
Advanced Undergraduate
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