To find \( f(40) \) using the function \( f(x) = \frac{9}{5}x + 32 \), substitute \( x = 40 \) into the equation:

\[
f(40) = \frac{9}{5}(40) + 32
\]

Now, calculate:

\[
f(40) = \frac{9 \times 40}{5} + 32 = \frac{360}{5} + 32 = 72 + 32 = 104
\]

So, \( f(40) = 104 \).

Would you like more details or have any questions?

Here are five related questions you can explore:
1. What is the slope of the function \( f(x) = \frac{9}{5}x + 32 \)?
2. How would you find the inverse of the function \( f(x) = \frac{9}{5}x + 32 \)?
3. What is the \( y \)-intercept of the function \( f(x) = \frac{9}{5}x + 32 \)?
4. How would the graph of \( f(x) \) change if the slope was doubled?
5. What is the domain and range of this linear function?

**Tip:** Linear functions like \( f(x) = \frac{9}{5}x + 32 \) always produce a straight line when graphed, and the slope tells you how steep that line is.

Discover how to solve the linear function f(x) = (9/5)x + 32 by finding f(40). This problem involves understanding linear functions, slope, and intercept. The solution includes step-by-step calculations for students in Grades 6-8.

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