The problem asks you to find $f(0)$ and $f(-2)$ given the function:

$f(x) = x^2 - 10x + 3$

Step-by-Step Solution:

1. Find $f(0)$: Substitute $x = 0$ into the function:

   $f(0) = (0)^2 - 10(0) + 3 = 0 - 0 + 3 = 3$

   So, $f(0) = 3$.

2. Find $f(-2)$: Substitute $x = -2$ into the function:

   $f(-2) = (-2)^2 - 10(-2) + 3$ $f(-2) = 4 + 20 + 3 = 27$

   So, $f(-2) = 27$.

Final Answers:

• $f(0) = 3$
• $f(-2) = 27$

Would you like more details or have any questions?

Here are some related questions to explore:

1. What are the zeros of the function $f(x) = x^2 - 10x + 3$?
2. What is the vertex of the quadratic function $f(x) = x^2 - 10x + 3$?
3. How do you find the axis of symmetry for a quadratic function?
4. What is the range of the function $f(x) = x^2 - 10x + 3$?
5. How do you determine if a quadratic function opens upwards or downwards?

Tip: When evaluating functions, always substitute carefully to ensure each step is correct!