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The problem asks you to find \( f(0) \) and \( f(-2) \) given the function:

\[
f(x) = x^2 - 10x + 3
\]

### Step-by-Step Solution:

1. **Find \( f(0) \):**
   Substitute \( x = 0 \) into the function:

   \[
   f(0) = (0)^2 - 10(0) + 3 = 0 - 0 + 3 = 3
   \]

   So, \( f(0) = 3 \).

2. **Find \( f(-2) \):**
   Substitute \( x = -2 \) into the function:

   \[
   f(-2) = (-2)^2 - 10(-2) + 3
   \]
   \[
   f(-2) = 4 + 20 + 3 = 27
   \]

   So, \( f(-2) = 27 \).

### Final Answers:
- \( f(0) = 3 \)
- \( f(-2) = 27 \)

Would you like more details or have any questions?

Here are some related questions to explore:
1. What are the zeros of the function \( f(x) = x^2 - 10x + 3 \)?
2. What is the vertex of the quadratic function \( f(x) = x^2 - 10x + 3 \)?
3. How do you find the axis of symmetry for a quadratic function?
4. What is the range of the function \( f(x) = x^2 - 10x + 3 \)?
5. How do you determine if a quadratic function opens upwards or downwards?

**Tip:** When evaluating functions, always substitute carefully to ensure each step is correct!

Given f(x) = x^2 - 10x + 3, find f(0) and f(-2).

Learn how to solve the quadratic function f(x) = x^2 - 10x + 3 by finding the values of f(0) and f(-2) with a step-by-step solution. Ideal for students in Grades 9-12.

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