Math Problem Statement

Given that triangles ΔCSE ~ ΔYJE, find EY.

Solution

We are given that triangles CSEYJE\triangle CSE \sim \triangle YJE, meaning they are similar. This allows us to set up a proportion between the corresponding sides of the two triangles to solve for EYEY.

Let's identify the corresponding sides based on the similarity:

  • CSYJ=SEJE=CEYE\frac{CS}{YJ} = \frac{SE}{JE} = \frac{CE}{YE}

Step-by-Step Solution:

  1. Identify Known Values and Expressions:

    • CS=18CS = 18
    • SE=x+1SE = x + 1
    • YJ=10YJ = 10
    • JE=x2JE = x - 2
  2. Set Up a Proportion: Since CSEYJE\triangle CSE \sim \triangle YJE, the ratios of corresponding sides are equal. We can use: CSYJ=SEJE\frac{CS}{YJ} = \frac{SE}{JE}

    Plugging in the values: 1810=x+1x2\frac{18}{10} = \frac{x + 1}{x - 2}

  3. Solve for xx: Cross-multiply to clear the fraction: 18(x2)=10(x+1)18(x - 2) = 10(x + 1) Expanding both sides: 18x36=10x+1018x - 36 = 10x + 10 Rearrange terms to isolate xx: 18x10x=36+1018x - 10x = 36 + 10 8x=468x = 46 x=468=5.75x = \frac{46}{8} = 5.75

  4. Calculate EYEY: Substitute x=5.75x = 5.75 into EY=x+1EY = x + 1: EY=5.75+1=6.75EY = 5.75 + 1 = 6.75

Answer:

EY=6.75EY = 6.75

Would you like more details or have any questions?


Related Questions:

  1. How do you determine corresponding sides in similar triangles?
  2. What other ratios could we use if different values were given?
  3. How do you handle proportions when variables appear on both sides of the fraction?
  4. Why is it important that the triangles are similar?
  5. Can you solve for JEJE if given EYEY?

Tip:

When dealing with similar triangles, always double-check the order of corresponding sides to avoid mistakes in setting up proportions.

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Math Problem Analysis

Mathematical Concepts

Similar Triangles
Proportion
Algebra

Formulas

Proportion of similar triangles: (Side1 of Triangle1) / (Corresponding Side1 of Triangle2) = (Side2 of Triangle1) / (Corresponding Side2 of Triangle2)
Cross-multiplication to solve proportions

Theorems

Triangle Similarity Theorem

Suitable Grade Level

Grade 9-10