Math Problem Statement

Find dy dx using partial derivatives. exy + y^ ey = 6

Solution

To find dydx\frac{dy}{dx} using partial derivatives for the given equation:

exy+yey=6e^{xy} + y e^{y} = 6

we will implicitly differentiate both sides of the equation with respect to xx, treating yy as a function of xx (i.e., y=y(x)y = y(x)).

Step 1: Differentiate the first term exye^{xy}

Using the chain rule: ddx(exy)=exyddx(xy)=exy(y+xdydx)\frac{d}{dx} \left( e^{xy} \right) = e^{xy} \cdot \frac{d}{dx}(xy) = e^{xy} \left( y + x \frac{dy}{dx} \right) (where dydx\frac{dy}{dx} is the derivative of yy with respect to xx).

Step 2: Differentiate the second term yeyy e^y

This is a product of two functions, so we apply

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Math Problem Analysis

Mathematical Concepts

Implicit Differentiation
Partial Derivatives
Chain Rule

Formulas

Implicit differentiation: d/dx [f(x, y)] = ∂f/∂x + (∂f/∂y) * dy/dx
Chain Rule: d/dx [f(g(x))] = f'(g(x)) * g'(x)

Theorems

Chain Rule

Suitable Grade Level

Undergraduate Calculus