Math Problem Statement

y=x^2 -3 find domain range

Solution

To find the domain and range of the function y=x23y = x^2 - 3, let's analyze the function step by step.

Domain:

The domain of a function consists of all the possible input values (x-values) that the function can accept. For the function y=x23y = x^2 - 3:

  • The function involves a polynomial expression, x2x^2, which is defined for all real numbers.
  • There are no restrictions like division by zero or square roots of negative numbers.

Domain: The domain is all real numbers, which can be written as: Domain=(,)\text{Domain} = (-\infty, \infty)

Range:

The range of a function consists of all the possible output values (y-values) that the function can produce.

  • The expression x2x^2 is always non-negative (i.e., x20x^2 \geq 0).
  • The smallest value of x2x^2 is 0, which occurs when x=0x = 0. So, the smallest value of yy is: y=023=3y = 0^2 - 3 = -3
  • As x2x^2 increases (as xx moves away from 0 in either direction), yy increases without bound.

Range: The range is all real numbers greater than or equal to 3-3, which can be written as: Range=[3,)\text{Range} = [-3, \infty)

Would you like more details or have any questions? Here are some related questions you might find interesting:

  1. How would the domain and range change if the function was y=x23y = \sqrt{x^2 - 3}?
  2. What is the vertex of the parabola represented by the function y=x23y = x^2 - 3?
  3. How does shifting the function vertically affect the range?
  4. What would the domain and range be for the function y=x2+2x3y = x^2 + 2x - 3?
  5. How can we determine the axis of symmetry for the function y=x23y = x^2 - 3?

Tip: For any quadratic function in the form y=ax2+bx+cy = ax^2 + bx + c, the vertex is the point that gives the minimum or maximum value of the function, which is useful in determining the range.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions

Formulas

y = ax^2 + bx + c

Theorems

Properties of Quadratic Functions

Suitable Grade Level

Grades 8-10