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Let's analyze the graph and problem you've provided:

The graph shows the relationship between the **minutes driven** (x-axis) and the **distance from the destination** (y-axis). The scenario describes a student driving back to college over 180 minutes at a constant speed of 40 miles per hour. 

### Step-by-step analysis:

1. **Time Driven (Domain)**:  
   The drive lasts **180 minutes**, starting at 0 minutes (departure) and ending at 180 minutes (arrival).  
   Thus, the domain represents the time of the drive:
   - **Domain:** [0, 180] (in minutes).

2. **Distance from Destination (Range)**:  
   Since the student is driving at 40 miles per hour for 180 minutes (or 3 hours), the total distance traveled is:
   \[
   40 \, \text{miles/hour} \times 3 \, \text{hours} = 120 \, \text{miles}.
   \]
   The graph starts at 120 miles (when the student starts the journey) and decreases to 0 miles (when the student reaches the destination).  
   Thus, the range is the distance from 0 to 120 miles:
   - **Range:** [0, 120] (in miles).

### Final Answer:
- **Domain:** [0, 180] (minutes).
- **Range:** [0, 120] (miles).

Let me know if you want further details or have any other questions!

Here are some related questions:
1. How can we calculate the slope of the graph?
2. What does the slope of the line represent in this context?
3. How would the domain and range change if the speed were different?
4. What happens to the range if the drive took longer than 180 minutes?
5. How would you model this scenario using a linear equation?

**Tip**: The slope of a graph in a distance-time relationship represents the speed of travel!

A student is driving back to college to start the fall semester. The drive takes 180 minutes when traveling at 40 miles per hour. What is the domain and range of the situation?

Learn how to determine the domain and range for a linear function representing a student's journey back to college over 180 minutes at 40 miles per hour. This problem focuses on understanding the relationship between time driven and distance from destination, suitable for Grades 8-10.

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