Math Problem Statement
you construct an open box with a square base (see figure) from 189 square inches of material. The height of the box is 3 inches.
A rectangular prism has a square base and the top face removed. The length is labeled x, the width is labeled x and the height is labeled 3 in. What are the dimensions of the box in inches? (Hint: The surface area is S = x2 + 4xh.)
Solution
To solve this problem, we need to use the given surface area formula and the given dimensions of the box to find the value of , which is the length of the sides of the square base.
Given Information:
- The surface area of the material used is 189 square inches.
- The height of the box is 3 inches.
- The formula for the surface area is:
where:
- is the surface area,
- is the length of one side of the square base,
- is the height of the box.
Since the height of the box is 3 inches, we can substitute and into the formula.
Simplifying the equation:
Now, we solve this quadratic equation for .
Step 1: Rearrange the equation
Step 2: Solve the quadratic equation
We can use the quadratic formula:
For this equation, , , and .
Now, let's calculate the value of .The two solutions for are:
Since the length of the side of the base must be positive, we discard the negative solution. Therefore, the value of is 9 inches.
Dimensions of the box:
- The side length of the square base is inches.
- The height of the box is inches.
Thus, the dimensions of the box are:
- inches.
Would you like more details on the solution process, or do you have any questions?
Related Questions:
- How would the formula change if the height of the box were different?
- How can you calculate the volume of this open box?
- What would the surface area be if the height increased to 5 inches?
- How can you solve the quadratic equation using factoring instead of the quadratic formula?
- How would the dimensions change if the surface area increased to 250 square inches?
Tip:
Always double-check units when solving geometry problems to ensure you're calculating areas, volumes, and dimensions in the correct units.
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Math Problem Analysis
Mathematical Concepts
Algebra
Quadratic Equations
Geometry
Formulas
Surface area formula: S = x^2 + 4xh
Quadratic equation formula: ax^2 + bx + c = 0
Theorems
Quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a
Suitable Grade Level
Grades 8-10
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