Math Problem Statement

図において,AC=4,BD=9であるとき,直径ABの長さを求めなさい。ただし直線CDは円Oの接線,点Pは接点である。

図において,AC=4,BD=9であるとき,直径ABの長さを求めなさい。ただし直線CDは円Oの接線,点Pは接点である。

Solution

The problem in the image presents a circle with diameter ABAB, and lines ACAC and BDBD are perpendicular to ABAB, with CDCD being a tangent to the circle. Points AA, BB, and OO are collinear, with OO being the center of the circle, and PP is the point where the tangent CDCD touches the circle.

Given:

  • AC=4AC = 4
  • BD=9BD = 9

We are tasked with finding the length of the diameter ABAB.

Approach

  1. Let the radius of the circle be rr, so the diameter AB=2rAB = 2r.
  2. Since CDCD is a tangent to the circle at point PP, we can use the fact that the tangent to a circle is perpendicular to the radius at the point of tangency. Thus, OPOP is perpendicular to CDCD.
  3. Applying the Pythagorean theorem to triangles AOCAOC and BODBOD, we can use the right triangle properties.

Let me perform the calculations to determine the length of ABAB.It seems that there was an issue in my approach. Let's revise the setup and proceed step by step.

We know:

  1. AB=2rAB = 2r (the diameter of the circle).
  2. AC=4AC = 4 and BD=9BD = 9, both are perpendicular to the diameter.
  3. CDCD is a tangent to the circle, meaning the distance from the center OO to CDCD equals the radius rr.

We can apply the power of a point theorem (also known as the tangent-secant theorem). This theorem relates the lengths of tangents and secants (or chords) drawn from a point to a circle.

For point CC (or point DD): AC2=AP×ABAC^2 = AP \times AB BD2=BP×ABBD^2 = BP \times AB

Let me now recalculate using this correct approach.The solution yields AB=42AB = -4\sqrt{2}, but since the length of a geometric figure cannot be negative, we take the positive value. Therefore, the length of the diameter ABAB is:

AB=42AB = 4\sqrt{2}

Numerically, this is approximately:

AB5.66AB \approx 5.66

Let me know if you would like a more detailed breakdown or further clarifications.

Here are five related questions for deeper understanding:

  1. How is the power of a point theorem applied in other geometric configurations?
  2. Why is the radius perpendicular to the tangent at the point of contact?
  3. What are the properties of tangents to circles that make them useful in solving problems like this?
  4. How would the result change if ACAC and BDBD had different values?
  5. Can the Pythagorean theorem be applied to other parts of this diagram?

Tip: The power of a point theorem is a powerful tool for solving problems involving tangents and secants from a point outside a circle.

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Math Problem Analysis

Mathematical Concepts

Geometry
Circles
Tangents

Formulas

Power of a point theorem
Pythagorean theorem

Theorems

Power of a point theorem
Tangent-radius theorem

Suitable Grade Level

Grades 9-12