Math Problem Statement
図において,AC=4,BD=9であるとき,直径ABの長さを求めなさい。ただし直線CDは円Oの接線,点Pは接点である。
Solution
The problem in the image presents a circle with diameter , and lines and are perpendicular to , with being a tangent to the circle. Points , , and are collinear, with being the center of the circle, and is the point where the tangent touches the circle.
Given:
We are tasked with finding the length of the diameter .
Approach
- Let the radius of the circle be , so the diameter .
- Since is a tangent to the circle at point , we can use the fact that the tangent to a circle is perpendicular to the radius at the point of tangency. Thus, is perpendicular to .
- Applying the Pythagorean theorem to triangles and , we can use the right triangle properties.
Let me perform the calculations to determine the length of .It seems that there was an issue in my approach. Let's revise the setup and proceed step by step.
We know:
- (the diameter of the circle).
- and , both are perpendicular to the diameter.
- is a tangent to the circle, meaning the distance from the center to equals the radius .
We can apply the power of a point theorem (also known as the tangent-secant theorem). This theorem relates the lengths of tangents and secants (or chords) drawn from a point to a circle.
For point (or point ):
Let me now recalculate using this correct approach.The solution yields , but since the length of a geometric figure cannot be negative, we take the positive value. Therefore, the length of the diameter is:
Numerically, this is approximately:
Let me know if you would like a more detailed breakdown or further clarifications.
Here are five related questions for deeper understanding:
- How is the power of a point theorem applied in other geometric configurations?
- Why is the radius perpendicular to the tangent at the point of contact?
- What are the properties of tangents to circles that make them useful in solving problems like this?
- How would the result change if and had different values?
- Can the Pythagorean theorem be applied to other parts of this diagram?
Tip: The power of a point theorem is a powerful tool for solving problems involving tangents and secants from a point outside a circle.
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Math Problem Analysis
Mathematical Concepts
Geometry
Circles
Tangents
Formulas
Power of a point theorem
Pythagorean theorem
Theorems
Power of a point theorem
Tangent-radius theorem
Suitable Grade Level
Grades 9-12
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