Math Problem Statement
Use the graph of f(x)=1/x
below to find a number δ
such that |f(x)−0.5|<0.1
whenever 0<|x−2|<δ
.
Solution
The graph provided is of the function . We are tasked with finding a number such that:
whenever .
Step-by-step process:
-
Express the condition: We need to satisfy the condition , where . Substituting this into the inequality, we get:
-
Simplify the inequality: To simplify this, we first rewrite the absolute value expression: This becomes:
-
Solve for : To solve this inequality, we first multiply both sides by (assuming , since the graph is valid for ):
-
Consider the two cases:
- Case 1: and
- Case 2:
Let's solve these two cases. I will calculate the solution. sympy import symbols, Eq, solve
Define variables
x = symbols('x')
Case 1: 2 - x < 0.2x
eq1 = Eq(2 - x, 0.2 * x) sol_case1 = solve(eq1, x)
Case 2: -(2 - x) < 0.2x
eq2 = Eq(-(2 - x), 0.2 * x) sol_case2 = solve(eq2, x)
sol_case1, sol_case2The solutions to the two cases are:
- For Case 1:
- For Case 2:
Interpretation of the results:
The inequality holds when lies between these two values, i.e., for .
Therefore, the value of should be the smallest distance from to the boundary points 1.67 and 2.5. The closest boundary is at , and the distance from 2 to 2.5 is:
Thus, .
Would you like further clarification or details on this solution?
Additional questions for you:
- How do you verify the value of in real-world applications?
- How would this problem change if the function were different, say ?
- What is the significance of the condition in terms of the graph?
- Can you extend this method to find a similar for any function ?
- How does the concept of limits relate to the condition ?
Tip: When solving inequalities like this, it helps to break the absolute value into cases to simplify the expression!
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Math Problem Analysis
Mathematical Concepts
Graph Analysis
Inequalities
Limits
Formulas
f(x) = 1/x
|f(x) - 0.5| < 0.1
Theorems
Epsilon-Delta Definition of Limits
Suitable Grade Level
Undergraduate Mathematics or Advanced High School (Grades 11-12)