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The problem is asking for the current through resistor \( R_5 \) in the given circuit, where we have five resistors and a battery with a given voltage. To calculate the current, we need to first determine the equivalent resistance of the circuit.

### Steps to approach the problem:

1. **Identify the resistors’ connections**: The resistors \( R_1, R_2, R_3, R_4, R_5 \) may be connected in series and/or parallel, so we need to simplify the circuit.
   
2. **Find the total resistance**: Calculate the equivalent resistance \( R_{\text{eq}} \) of the circuit using series and parallel rules.

    - **Series connection**: For resistors in series, the total resistance is the sum of individual resistances:
      \[
      R_{\text{total}} = R_1 + R_2 + R_3 + \dots
      \]
      
    - **Parallel connection**: For resistors in parallel, the total resistance is found by:
      \[
      \frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \dots
      \]

3. **Use Ohm’s Law**: Once the total resistance is found, use Ohm's Law to calculate the total current \( I_{\text{total}} \):
   \[
   I_{\text{total}} = \frac{V}{R_{\text{eq}}}
   \]
   where \( V \) is the voltage of the battery.

4. **Current through \( R_5 \)**: Once we find the current in the circuit, the current through each resistor can be determined based on the configuration of the resistors (whether in series or parallel).

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Five resistors, R1 = 3.5 Ω, R2 = 8.8 Ω, R3 = 6.0 Ω, R4 = 8.8 Ω, and R5 = 6.0 Ω are connected as shown in the picture. The battery provides voltage ε = 17.5 V. What is the current through resistor R5?

Learn how to calculate the current through resistor R5 in a mixed-series and parallel resistor circuit using Ohm’s Law and circuit analysis techniques. Given resistor values and a 17.5V battery, this problem demonstrates how to find the equivalent resistance and determine current flow. Suitable for Grades 10-12.

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