https://file.aiquickdraw.com/mathbot/file/1727077688861m6ggdu4i.jpg

The problem in the image asks for the value of \(\cos A\) in the right triangle \(ABC\), where:

- \(AB = 43\) (the hypotenuse),
- \(AC = 42\) (the adjacent side to angle \(A\)),
- \(BC\) is the unknown (the opposite side to angle \(A\)).

For any right triangle, the cosine of angle \(A\) is given by:

\[
\cos A = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{AC}{AB}
\]

Substituting the known values:

\[
\cos A = \frac{42}{43}
\]

Thus, the value of \(\cos A\) is \(\frac{42}{43}\), which corresponds to option **A**.

Would you like more details or have any other questions? Here are some related questions you can consider:

1. How do you calculate the sine of angle \(A\)?
2. What is the value of \(BC\) using the Pythagorean theorem?
3. How do you calculate the tangent of angle \(A\)?
4. What is the value of \(\cos B\) for this triangle?
5. How do trigonometric functions apply in solving real-world problems?

**Tip:** In a right triangle, you can always use basic trigonometric ratios to find unknown angles and sides efficiently.

What is the value of cos A in the triangle shown, where AB = 43 (hypotenuse) and AC = 42 (adjacent side)?

Solve a trigonometry problem involving a right triangle where AB = 43 and AC = 42. Learn how to calculate cos A using the formula cos A = adjacent / hypotenuse. Suitable for Grades 9-11.

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