Math Problem Statement

Min P = 40x + 30y 10x + 16y ≥ 6,000 10x + 8y ≤ 3,600 x,y ≥ 0 Give the corners of the feasible set.

Solution

To find the corners (vertices) of the feasible set for the given linear programming problem, we need to determine the points of intersection between the constraints and check where these points satisfy all the inequalities.

Step 1: Write down the constraints

  1. 10x+16y600010x + 16y \geq 6000
  2. 10x+8y360010x + 8y \leq 3600
  3. x0x \geq 0
  4. y0y \geq 0

Step 2: Solve the inequalities as equations to find intersection points

We'll solve the following pairs of equations:

  1. Intersection of 10x+16y=600010x + 16y = 6000 and 10x+8y=360010x + 8y = 3600:

    10x + 16y &= 6000 \quad \text{(Equation 1)} \\ 10x + 8y &= 3600 \quad \text{(Equation 2)} \end{aligned}$$ Subtract Equation 2 from Equation 1: $$(10x + 16y) - (10x + 8y) = 6000 - 3600$$ $$8y = 2400 \implies y = 300$$ Substitute $$y = 300$$ into Equation 2: $$10x + 8(300) = 3600 \implies 10x + 2400 = 3600 \implies 10x = 1200 \implies x = 120$$ So, the point of intersection is $$(120, 300)$$.
  2. Intersection of 10x+16y=600010x + 16y = 6000 and y=0y = 0 (x-axis): 10x+16(0)=6000    10x=6000    x=60010x + 16(0) = 6000 \implies 10x = 6000 \implies x = 600 So, the point is (600,0)(600, 0).

  3. Intersection of 10x+8y=360010x + 8y = 3600 and y=0y = 0 (x-axis): 10x+8(0)=3600    10x=3600    x=36010x + 8(0) = 3600 \implies 10x = 3600 \implies x = 360 So, the point is (360,0)(360, 0).

  4. Intersection of x=0x = 0 (y-axis) and 10x+16y=600010x + 16y = 6000: 10(0)+16y=6000    16y=6000    y=37510(0) + 16y = 6000 \implies 16y = 6000 \implies y = 375 So, the point is (0,375)(0, 375).

  5. Intersection of x=0x = 0 (y-axis) and 10x+8y=360010x + 8y = 3600: 10(0)+8y=3600    8y=3600    y=45010(0) + 8y = 3600 \implies 8y = 3600 \implies y = 450 So, the point is (0,450)(0, 450).

Step 3: Feasibility check

Now, let's identify the points that satisfy all the inequalities:

  1. (120,300)(120, 300)
  2. (600,0)(600, 0)
  3. (360,0)(360, 0)
  4. (0,375)(0, 375)

Conclusion

The corners of the feasible set are:

  • (120,300)(120, 300)
  • (600,0)(600, 0)
  • (360,0)(360, 0)
  • (0,375)(0, 375)

Would you like more details, or do you have any questions about the process?


Related Questions:

  1. How do you find the optimal solution given the objective function and feasible set?
  2. What role does the feasible region play in linear programming?
  3. Can a linear programming problem have multiple optimal solutions?
  4. How do boundary conditions affect the feasible set?
  5. How would the feasible set change if one of the constraints is altered?

Tip: Always check all vertices of the feasible set to find the optimal solution, as it will always lie at one of these points.

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Math Problem Analysis

Mathematical Concepts

Linear Programming
Inequalities
Feasible Region
Optimization

Formulas

10x + 16y = 6000
10x + 8y = 3600

Theorems

Feasible Set Intersection

Suitable Grade Level

Grades 10-12