Math Problem Statement
Min P = 40x + 30y 10x + 16y ≥ 6,000 10x + 8y ≤ 3,600 x,y ≥ 0 Give the corners of the feasible set.
Solution
To find the corners (vertices) of the feasible set for the given linear programming problem, we need to determine the points of intersection between the constraints and check where these points satisfy all the inequalities.
Step 1: Write down the constraints
Step 2: Solve the inequalities as equations to find intersection points
We'll solve the following pairs of equations:
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Intersection of and :
10x + 16y &= 6000 \quad \text{(Equation 1)} \\ 10x + 8y &= 3600 \quad \text{(Equation 2)} \end{aligned}$$ Subtract Equation 2 from Equation 1: $$(10x + 16y) - (10x + 8y) = 6000 - 3600$$ $$8y = 2400 \implies y = 300$$ Substitute $$y = 300$$ into Equation 2: $$10x + 8(300) = 3600 \implies 10x + 2400 = 3600 \implies 10x = 1200 \implies x = 120$$ So, the point of intersection is $$(120, 300)$$. -
Intersection of and (x-axis): So, the point is .
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Intersection of and (x-axis): So, the point is .
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Intersection of (y-axis) and : So, the point is .
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Intersection of (y-axis) and : So, the point is .
Step 3: Feasibility check
Now, let's identify the points that satisfy all the inequalities:
Conclusion
The corners of the feasible set are:
Would you like more details, or do you have any questions about the process?
Related Questions:
- How do you find the optimal solution given the objective function and feasible set?
- What role does the feasible region play in linear programming?
- Can a linear programming problem have multiple optimal solutions?
- How do boundary conditions affect the feasible set?
- How would the feasible set change if one of the constraints is altered?
Tip: Always check all vertices of the feasible set to find the optimal solution, as it will always lie at one of these points.
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Math Problem Analysis
Mathematical Concepts
Linear Programming
Inequalities
Feasible Region
Optimization
Formulas
10x + 16y = 6000
10x + 8y = 3600
Theorems
Feasible Set Intersection
Suitable Grade Level
Grades 10-12
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