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We are given that the sides of the square are 8 units long, and the square is aligned parallel to the axes. The point \( E(1, 5) \) is one vertex of the square.

The key to solving this is to recognize that each side of the square is 8 units long, and since the sides are parallel to the x-axis and y-axis, we can deduce the coordinates of the other vertices.

- The point \( E \) is at \( (1, 5) \).
- The side length is 8 units, so moving horizontally by 8 units from point \( E \) gives us the x-coordinate of point \( F \). The coordinates of \( F \) will be \( (1 + 8, 5) = (9, 5) \).
- Now, the point \( G \) lies directly below point \( F \), so the y-coordinate of \( G \) is 8 units down from 5. This gives us the coordinates of point \( G \) as \( (9, 5 - 8) = (9, -3) \).

Therefore, the coordinates of point \( G \) are \( (9, -3) \).

Would you like more details on the solution, or do you have any questions? Here are five related questions:

1. How would the coordinates change if the side length of the square were different?
2. What would happen if the square was rotated 45 degrees?
3. Can you calculate the area of the square using the given information?
4. How can you determine the coordinates of point \( H \) using the same method?
5. What if point \( E \) had different coordinates; how would that affect point \( G \)?

**Tip:** Whenever working with shapes aligned with axes, it helps to focus on how their dimensions affect coordinates along the x- and y-axes.

What are the coordinates of point G on the square?

Learn how to find the coordinates of point G on a square with sides of 8 units, aligned with the axes. This problem involves coordinate geometry, using translations and understanding the properties of squares. Suitable for students in Grades 7-10.

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