Math Problem Statement

36, 20, and 16 are the areas of the smaller triangles indicated below. If ABCD is a rectangle, find the area of the triangle PBQ.

Solution

We are given a rectangle ABCDABCD and asked to find the area of triangle PBQPBQ. The areas of the smaller triangles are labeled as follows:

  • Area of triangle APB=36APB = 36
  • Area of triangle BCQ=20BCQ = 20
  • Area of triangle PDQ=16PDQ = 16

Now let's work step by step:

  1. Since ABCDABCD is a rectangle, triangles that share the same height and are between the same parallel sides must have proportional areas based on their base lengths.

  2. The entire quadrilateral PBCQPBCQ is made up of triangles PBQPBQ, APBAPB, and BCQBCQ. Similarly, quadrilateral PDQPDQ includes triangles PDQPDQ and PBQPBQ.

  3. Let's assume the height from point BB to line ADAD is the same for all triangles. By comparing areas, we will find the base relationships and solve for the area of PBQPBQ.

I'll now perform the calculation to find the area of triangle PBQPBQ.

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Math Problem Analysis

Mathematical Concepts

Geometry
Triangle Area
Proportions

Formulas

Area of a triangle = (1/2) * base * height
Proportional areas of triangles between the same parallel sides in a rectangle

Theorems

Proportional Areas Theorem

Suitable Grade Level

Grades 9-11