To find the area of a trapezoid, we use the formula:

$\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}$

Here, we have the following values:

• Base 1 = 4 ft
• Base 2 = 10 ft
• Height = 8 ft

Substituting these into the formula:

$\text{Area} = \frac{1}{2} \times (4 + 10) \times 8$ $\text{Area} = \frac{1}{2} \times 14 \times 8$ $\text{Area} = 7 \times 8 = 56 \text{ ft}^2$

The correct answer is $56 \text{ ft}^2$.

Would you like more details or have any questions?

Here are 5 related questions for further practice:

1. How do you calculate the area of a triangle?
2. If the height was doubled, how would the area change?
3. How do you find the area of a parallelogram?
4. What is the area of a trapezoid with bases 5 ft, 12 ft, and a height of 7 ft?
5. How do you find the perimeter of a trapezoid?

Tip: For trapezoid problems, always add the lengths of both bases before multiplying by the height.