To find the area of a trapezoid, we use the following formula:

$\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}$

Given:

• Base 1 = 4 ft
• Base 2 = 6 ft
• Height = 10 ft

Substitute these values into the formula:

$\text{Area} = \frac{1}{2} \times (4 + 6) \times 10 = \frac{1}{2} \times 10 \times 10 = \frac{1}{2} \times 100 = 50 \, \text{ft}^2$

Thus, the area of the trapezoid is 50 square feet.

Let me know if you'd like more details or have any questions!

Here are 5 related questions you might find helpful:

1. What is the formula for the perimeter of a trapezoid?
2. How does the area formula differ for a parallelogram vs. a trapezoid?
3. If the height were doubled, how would the area of the trapezoid change?
4. Can you find the area of an isosceles trapezoid if only one base and height are given?
5. How does changing one of the bases affect the overall area?

Tip: Always ensure that the units are consistent when calculating areas—both the bases and height should be in the same units.