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To find the area of the given shape, we can treat it as a right triangle combined with a rectangle. Let's break it down:

1. The shape has two parts: a rectangle and a right triangle.
   - The rectangle has dimensions: 9 m by 2 m.
   - The right triangle has a base of 9 m and a height of 5 m.

2. **Area of the rectangle**: 
   \[
   \text{Area of rectangle} = \text{length} \times \text{width} = 9 \, \text{m} \times 2 \, \text{m} = 18 \, \text{m}^2
   \]

3. **Area of the triangle**: 
   \[
   \text{Area of triangle} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 9 \, \text{m} \times 5 \, \text{m} = 22.5 \, \text{m}^2
   \]

4. **Total area**:
   \[
   \text{Total area} = \text{Area of rectangle} + \text{Area of triangle} = 18 \, \text{m}^2 + 22.5 \, \text{m}^2 = 40.5 \, \text{m}^2
   \]

So, the total area of the shape is **40.5 m²**.

Would you like more details or have any questions on this? 

Here are 5 related questions to explore:
1. How do you calculate the area of a compound shape?
2. What happens if the angle of the triangle changes?
3. How does the Pythagorean theorem apply in this problem?
4. What is the perimeter of the shape?
5. How would you find the area of a trapezoid?

**Tip**: When calculating the area of a compound shape, break it down into simpler shapes (like rectangles, triangles, etc.) and find the area of each part separately.

Discover how to calculate the area of a composite shape with a rectangle and a right triangle. This step-by-step solution breaks down the process using key geometry formulas for rectangles and triangles. Suitable for students in Grades 6-8.

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