To find the area of the given shape, we divide it into two parts:

1. A rectangle on the left
2. A triangle on the right

Step 1: Area of the Rectangle

The dimensions of the rectangle are:

• Length = 15 m
• Height = 6 m

The area of a rectangle is given by:
$\text{Area of rectangle} = \text{Length} \times \text{Height}$
$\text{Area of rectangle} = 15 \times 6 = 90 \, \text{m}^2$

Step 2: Area of the Triangle

The base of the triangle is:

• Base = Total length - Length of rectangle = $21 - 15 = 6 \, \text{m}$
  The height of the triangle is the same as the rectangle:
• Height = 6 m

The area of a triangle is given by:
$\text{Area of triangle} = \frac{1}{2} \times \text{Base} \times \text{Height}$
$\text{Area of triangle} = \frac{1}{2} \times 6 \times 6 = 18 \, \text{m}^2$

Step 3: Total Area of the Shape

Now, we add the areas of the rectangle and triangle:
$\text{Total Area} = \text{Area of rectangle} + \text{Area of triangle}$
$\text{Total Area} = 90 + 18 = 108 \, \text{m}^2$

Final Answer:

The area of the shape is 108 m².

Let me know if you need further clarification!

Related Questions:

1. How do you find the area of a trapezium?
2. What is the area of a triangle if the base and height are doubled?
3. How can you calculate the perimeter of this shape?
4. What is the area of a rectangle when its length is tripled and width is doubled?
5. How do you calculate the area of composite shapes with curved edges?

Tip: Always divide complex shapes into basic geometric shapes (like rectangles and triangles) to simplify area calculations.