The problem in the image involves finding a factor pair for the number 56 and completing the equation. Let's work through the solution:

Given Equation:

$56 = 8 \times 7$

The instructions break apart the factor $8$ into $4 \times 2$: $56 = (4 \times 2) \times 7$

Then, the factors are regrouped: $56 = 4 \times (2 \times 7)$

Now, multiply inside the parentheses: $2 \times 7 = 14$

So, the completed equation is: $56 = 4 \times 14$

This shows that another factor pair of $56$ is $4$ and $14$.

Do you want further details or explanations? Let me know!

Here are 5 questions to expand understanding:

1. What are all the factor pairs of 56?
2. How do we systematically find factor pairs of a number?
3. Why does breaking apart factors help in simplifying multiplication problems?
4. Can the same strategy be used for other numbers, such as 72 or 45?
5. How is the distributive property used in this example?

Tip: When factoring, start by dividing the number by small primes (e.g., 2, 3, 5) to find all pairs efficiently.