Math Problem Statement

Given l || m || n, find the value of x where the angle adjacent to x is 124°.

Solution

In the given image, lines ll, mm, and nn are parallel, and we are tasked with finding the value of xx^\circ.

Step-by-Step Solution:

  1. Understand the setup:

    • We are told that lines lmnl \parallel m \parallel n, meaning these lines are parallel to each other.
    • There is a transversal cutting through these parallel lines.
    • One of the angles formed by this transversal is 124°, and the angle labeled xx^\circ is adjacent to it.
  2. Use the property of supplementary angles:

    • When a transversal crosses parallel lines, consecutive interior angles formed on the same side of the transversal are supplementary (i.e., their sum is 180°).
    • Here, the angle 124124^\circ and xx^\circ form a linear pair (adjacent angles along a straight line), so they are supplementary.
  3. Set up the equation: x+124=180x^\circ + 124^\circ = 180^\circ

  4. Solve for xx: x=180124=56x = 180^\circ - 124^\circ = 56^\circ

Final Answer:

x=56x = 56^\circ

Let me know if you'd like further clarification or have any questions.


Here are five related questions for practice:

  1. What is the sum of the interior angles on the same side of the transversal?
  2. If another angle on the transversal is given as 56°, what is the corresponding alternate interior angle?
  3. How would the problem change if the lines were not parallel?
  4. What is the relationship between corresponding angles when a transversal cuts through parallel lines?
  5. How do you identify supplementary angles in a diagram with parallel lines and a transversal?

Tip: Always look for linear pairs or alternate angles when dealing with parallel lines and transversals.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Parallel Lines
Transversals
Supplementary Angles

Formulas

x + 124° = 180°

Theorems

Supplementary Angles Theorem
Parallel Lines and Transversals Theorem

Suitable Grade Level

Grades 8-10