Math Problem Statement

If PR and SU are parallel lines and m∠PQT = 136°, what is m∠RQO?

Solution

In the given diagram, you have two parallel lines PRPR and SUSU with a transversal line intersecting them. You are provided with the information that:

  • PRSUPR \parallel SU
  • PQT=136\angle PQT = 136^\circ

You are asked to find the measure of RQO\angle RQO.

Since PRPR and SUSU are parallel lines, and PQTPQT and RQORQO are angles on the same side of the transversal, we can apply the concept of supplementary angles. Supplementary angles sum up to 180180^\circ.

The angles PQT\angle PQT and RQO\angle RQO form a linear pair, so:

PQT+RQO=180\angle PQT + \angle RQO = 180^\circ

Given that PQT=136\angle PQT = 136^\circ, we can solve for RQO\angle RQO:

RQO=180136=44\angle RQO = 180^\circ - 136^\circ = 44^\circ

Thus, the measure of RQO\angle RQO is 4444^\circ.

Would you like further explanation or details?

Related Questions:

  1. What are alternate interior angles, and how do they apply to parallel lines?
  2. How do we prove that two angles are supplementary?
  3. Can we identify any corresponding angles in this diagram?
  4. What is the definition of a transversal, and how does it affect parallel lines?
  5. What other angle relationships can be found in this diagram?

Tip: Always remember that angles on a straight line (linear pair) add up to 180180^\circ.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Transversals
Parallel Lines
Angle Relationships
Linear Pair

Formulas

m∠PQT + m∠RQO = 180°

Theorems

Linear Pair Theorem
Supplementary Angles

Suitable Grade Level

Grades 8-10