The problem involves a rhombus $QRST$, and we need to determine the measure of $\angle SUT$.

Key properties of a rhombus:

1. All sides are equal in length.
2. The diagonals bisect each other at right angles (90°).
3. The diagonals bisect the angles of the rhombus.

Observations in the diagram:

• $\overline{SU}$ and $\overline{QT}$ are diagonals of rhombus $QRST$, and they intersect at point $U$.
• Since the diagonals bisect each other at 90°, $\angle SUT = 90^\circ$.

Conclusion:

The measure of $\angle SUT$ is: $\boxed{90^\circ}$

Would you like me to explain the reasoning further or provide any additional insights?

Here are 5 related questions for further exploration:

1. What are the measures of the other angles formed at $U$ by the diagonals of the rhombus?
2. How do the diagonals of a rhombus relate to the side lengths?
3. Can you prove that the diagonals of a rhombus always bisect the angles?
4. What are the properties of the diagonals in a parallelogram, and how do they compare with those of a rhombus?
5. If the length of $\overline{SU}$ is 10 and $\overline{QT}$ is 24, what is the length of $\overline{QU}$?

Tip: Always remember that the diagonals of a rhombus not only bisect the angles but also intersect perpendicularly, which is a key difference compared to a general parallelogram.