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The problem provides three angles of a quadrilateral (A, B, C) and asks for the fourth angle (D). Specifically, we know:

- \( \angle A = 115^\circ \)
- \( \angle B = 136^\circ \)
- \( \angle C = 38^\circ \)

In any quadrilateral, the sum of all interior angles is always 360 degrees. Using this fact, we can determine the value of \( \angle D \) by summing the known angles and subtracting from 360°.

Here's the calculation:

\[
\angle D = 360^\circ - (\angle A + \angle B + \angle C)
\]

Substitute the given values:

\[
\angle D = 360^\circ - (115^\circ + 136^\circ + 38^\circ)
\]

\[
\angle D = 360^\circ - 289^\circ = 71^\circ
\]

Thus, \( \angle D = 71^\circ \).

Would you like more details, or do you have any questions?

### Follow-up Questions:
1. What is the formula to find the sum of angles in a polygon?
2. How does the sum of angles change for different polygons (triangle, pentagon, etc.)?
3. Why do quadrilaterals always have a total of 360°?
4. Can you use this method for irregular quadrilaterals as well?
5. How would the problem change if one of the angles were unknown instead of three?

#### Tip:
Remember, the sum of interior angles of any polygon can be calculated using the formula \( (n-2) \times 180^\circ \), where \( n \) is the number of sides of the polygon.

You are asked to fabricate the following shape. What is the size of angle D in the diagram? Angles A, B, and C are 115°, 136°, and 38°, respectively.

Calculate the size of angle D in a quadrilateral where angles A, B, and C are given as 115°, 136°, and 38°, respectively. Using the interior angle sum formula, this problem helps students in grades 6-8 understand key concepts in geometry.

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