Math Problem Statement

Arifmetik progressiyada a₁=3 va d=2 bo'lsa, a₉ qiymatini toping.

Solution

The image you uploaded is asking about an arithmetic progression (AP). The question provides the first term a1=3a_1 = 3 and the common difference d=2d = 2, and is asking to find the value of a9a_9, the 9th term of the AP.

We can use the formula for the nth term of an arithmetic progression:

an=a1+(n1)da_n = a_1 + (n - 1) \cdot d

Where:

  • ana_n is the nth term
  • a1a_1 is the first term
  • dd is the common difference
  • nn is the position of the term

For this problem, we want to find a9a_9, so we substitute a1=3a_1 = 3, d=2d = 2, and n=9n = 9 into the formula:

a9=3+(91)2a_9 = 3 + (9 - 1) \cdot 2

Now, calculate the value:

a9=3+82a_9 = 3 + 8 \cdot 2 a9=3+16a_9 = 3 + 16 a9=19a_9 = 19

So, the 9th term a9a_9 is 1919, which corresponds to option B.

Let me know if you'd like more details or if you have any questions.

Related Questions:

  1. How can you determine the sum of the first nn terms of an arithmetic progression?
  2. What would happen if the common difference dd were negative in this sequence?
  3. How do you find the 15th term of an arithmetic progression where a1=5a_1 = 5 and d=4d = 4?
  4. Can you describe the relationship between the terms in an arithmetic progression graphically?
  5. What happens if the common difference dd is zero in an arithmetic progression?

Tip: Practice calculating terms and sums of arithmetic progressions to become more comfortable with the formulas.