Math Problem Statement

Here are the the additional activity, from the given Fibonacci sequence 0,1,1,2,3,5,8,11,13.......Find the 50th term and 75th term using Binets formula , show your solution

Solution

To find the 50th and 75th terms of the Fibonacci sequence using Binet's formula, we'll proceed step by step.

Binet's Formula

The formula for the nn-th term F(n)F(n) of the Fibonacci sequence is given by:

F(n)=ϕnψn5F(n) = \frac{\phi^n - \psi^n}{\sqrt{5}}

where:

ϕ=1+521.6180339887(the golden ratio)\phi = \frac{1 + \sqrt{5}}{2} \approx 1.6180339887 \quad \text{(the golden ratio)} ψ=1520.6180339887\psi = \frac{1 - \sqrt{5}}{2} \approx -0.6180339887

Finding the 50th Term F(50)F(50)

Using Binet's formula:

F(50)=ϕ50ψ505F(50) = \frac{\phi^{50} - \psi^{50}}{\sqrt{5}}

Since ψ\psi is a negative number less than 1, ψ50\psi^{50} will be very close to 0, so it can be approximated as:

F(50)ϕ505F(50) \approx \frac{\phi^{50}}{\sqrt{5}}

Let's calculate F(50)F(50):

  1. Calculate ϕ50\phi^{50}: ϕ501.618033988750\phi^{50} \approx 1.6180339887^{50}

  2. Approximate ψ50\psi^{50}: \psi^{50} \approx (-0.6180339887)^{50} \approx 0 \text{ (since \psi^{50} is extremely small)}

  3. Calculate F(50)F(50): F(50)ϕ505F(50) \approx \frac{\phi^{50}}{\sqrt{5}}

Let's approximate this using the values:

ϕ5028143753123.000002\phi^{50} \approx 28143753123.000002 52.2360679775\sqrt{5} \approx 2.2360679775 F(50)28143753123.0000022.236067977512586269025F(50) \approx \frac{28143753123.000002}{2.2360679775} \approx 12586269025

Finding the 75th Term F(75)F(75)

Similarly, for the 75th term:

F(75)=ϕ75ψ755F(75) = \frac{\phi^{75} - \psi^{75}}{\sqrt{5}}

Again, ψ75\psi^{75} will be very close to 0, so:

F(75)ϕ755F(75) \approx \frac{\phi^{75}}{\sqrt{5}}

Let's calculate F(75)F(75):

  1. Calculate ϕ75\phi^{75}: ϕ751.618033988775\phi^{75} \approx 1.6180339887^{75}

  2. Approximate ψ75\psi^{75}: ψ75(0.6180339887)750\psi^{75} \approx (-0.6180339887)^{75} \approx 0

  3. Calculate F(75)F(75): F(75)ϕ755F(75) \approx \frac{\phi^{75}}{\sqrt{5}}

Let's approximate this using the values:

ϕ7517167680177565.025\phi^{75} \approx 17167680177565.025 52.2360679775\sqrt{5} \approx 2.2360679775 F(75)17167680177565.0252.2360679775767761997860F(75) \approx \frac{17167680177565.025}{2.2360679775} \approx 767761997860

Final Answers:

  • The 50th term of the Fibonacci sequence is approximately 12,586,269,025.
  • The 75th term of the Fibonacci sequence is approximately 767,761,997,860.

Would you like more details or have any other questions?


Here are some related questions:

  1. How does Binet’s formula relate to the Fibonacci sequence?
  2. What is the significance of the golden ratio ϕ\phi in Fibonacci numbers?
  3. Can Binet’s formula be used for non-integer values of nn?
  4. What is the limit of the ratio F(n+1)/F(n)F(n+1)/F(n) as nn approaches infinity?
  5. How would the solution change if the Fibonacci sequence started with different initial values?

Tip: In calculations involving large Fibonacci numbers, it's useful to recognize that ψn\psi^n becomes negligible as nn increases, simplifying the computation.

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Math Problem Analysis

Mathematical Concepts

Sequences and Series
Fibonacci Sequence
Exponential Functions

Formulas

Binet's Formula: F(n) = (φ^n - ψ^n) / √5
Golden Ratio: φ = (1 + √5) / 2
ψ = (1 - √5) / 2

Theorems

Binet's Theorem

Suitable Grade Level

Grades 10-12