Math Problem Statement

Find the 15th term of the Fibonacci sequence if the 10th term and 11th terms are 34 and 55 respectively

Solution

To find the 15th term of the Fibonacci sequence, we can use the information provided: the 10th term is 34, and the 11th term is 55. The Fibonacci sequence is defined by the recurrence relation:

F(n)=F(n1)+F(n2)F(n) = F(n-1) + F(n-2)

Given:

  • F(10)=34F(10) = 34
  • F(11)=55F(11) = 55

We can calculate the subsequent terms:

F(12)=F(11)+F(10)=55+34=89F(12) = F(11) + F(10) = 55 + 34 = 89 F(13)=F(12)+F(11)=89+55=144F(13) = F(12) + F(11) = 89 + 55 = 144 F(14)=F(13)+F(12)=144+89=233F(14) = F(13) + F(12) = 144 + 89 = 233 F(15)=F(14)+F(13)=233+144=377F(15) = F(14) + F(13) = 233 + 144 = 377

Thus, the 15th term of the Fibonacci sequence is 377.

Would you like a more detailed explanation or have any other questions?

Here are 5 related questions you might find interesting:

  1. What is the 20th term of the Fibonacci sequence?
  2. How do you derive the general formula for the nth term in the Fibonacci sequence?
  3. Can you prove that the Fibonacci sequence grows exponentially?
  4. What is the sum of the first 15 terms of the Fibonacci sequence?
  5. How can the Fibonacci sequence be applied in real-life scenarios?

Tip: The ratio of consecutive Fibonacci numbers approximates the Golden Ratio (ϕ1.618\phi \approx 1.618) as the sequence progresses.

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Math Problem Analysis

Mathematical Concepts

Fibonacci Sequence

Formulas

F(n) = F(n-1) + F(n-2)

Theorems

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Suitable Grade Level

High School