To find the squirrel's final horizontal velocity right before it lands, we can analyze the situation carefully:

• In projectile motion, the horizontal velocity remains constant (if we ignore air resistance). This is because there is no horizontal force acting on the squirrel, so no acceleration in the horizontal direction.

Given:

• Initial horizontal velocity = $10 \, \text{m/s}$
• Time of flight = $3 \, \text{seconds}$

Since there is no horizontal acceleration, the final horizontal velocity right before landing will be the same as the initial horizontal velocity.

Thus, the final horizontal velocity is: $v_{\text{horizontal}} = 10 \, \text{m/s}$

Would you like details on the vertical velocity or other aspects of this problem?

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Here are 5 related questions you might find helpful:

1. What would be the squirrel's final vertical velocity right before it lands?
2. How far horizontally does the squirrel travel in 3 seconds?
3. What is the total time of flight for a projectile launched horizontally from a different height?
4. How would air resistance affect the squirrel's horizontal velocity?
5. Can you calculate the squirrel's final speed (considering both horizontal and vertical velocities)?

Tip: In projectile motion, horizontal and vertical components are independent of each other, with gravity only affecting the vertical motion.