Math Problem Statement

A Ferris wheel is 30 meters in diameter and is raised on a platform 8 feet from the ground so that the bottom of the wheel is in line with the top of the platform. A ride lasts 20 minutes and undergoes five revolutions in a clockwise direction during this time. If Brad is sitting in a pod in position A at time t = 0 minutes, determine his position when he reaches B and E.

B: (1, 23) and E: (4, 38) B: (4, 23) and E: (16, 38) B: (1, 53) and E: (4, 68) B: (4, 53) and E: (16, 68)

Solution

To determine Brad's position on the Ferris wheel at points B and E, we need to analyze the movement of the wheel.

Key Information

  • Diameter of the Ferris wheel: 30 meters (radius = 15 meters)
  • Height of the platform: 8 feet (approximately 2.44 meters)
  • Total ride time: 20 minutes
  • Total revolutions: 5 revolutions

Calculating Angular Speed

  1. Total time of ride in seconds: 20 minutes=20×60=1200 seconds20 \text{ minutes} = 20 \times 60 = 1200 \text{ seconds}
  2. Angular speed (in radians per second): Total angle=5×2π=10π radians\text{Total angle} = 5 \times 2\pi = 10\pi \text{ radians} Angular speed=10π1200=π120 radians/second\text{Angular speed} = \frac{10\pi}{1200} = \frac{\pi}{120} \text{ radians/second}

Position Calculation

Brad's position can be modeled using parametric equations based on the angle of rotation θ\theta:

  • Vertical position (height): y(t)=2.44+15(1cos(θ(t)))y(t) = 2.44 + 15(1 - \cos(\theta(t)))
  • Horizontal position: (not necessary for this problem, but can be given by) x(t)=15sin(θ(t))x(t) = 15\sin(\theta(t))

Time Calculation for Points

To find the positions at points B and E:

  1. For B and E:
    • Convert the minutes into seconds for calculations.
    • Calculate the angle at each time by using: θ(t)=π120t\theta(t) = \frac{\pi}{120} t
    • Plug tt values into the y(t)y(t) equation to find the height at those times.

For B:

  • At t=1t = 1 minute = 60 seconds: θ(60)=π120×60=π2\theta(60) = \frac{\pi}{120} \times 60 = \frac{\pi}{2} y(60)=2.44+15(1cos(π2))=2.44+15(10)=17.44 metersy(60) = 2.44 + 15(1 - \cos(\frac{\pi}{2})) = 2.44 + 15(1 - 0) = 17.44 \text{ meters}

  • At t=4t = 4 minutes = 240 seconds: θ(240)=π120×240=2π\theta(240) = \frac{\pi}{120} \times 240 = 2\pi y(240)=2.44+15(1cos(2π))=2.44+15(11)=2.44 metersy(240) = 2.44 + 15(1 - \cos(2\pi)) = 2.44 + 15(1 - 1) = 2.44 \text{ meters}

For E:

  • At t=16t = 16 minutes = 960 seconds: θ(960)=π120×960=8π\theta(960) = \frac{\pi}{120} \times 960 = 8\pi y(960)=2.44+15(1cos(8π))=2.44+15(11)=2.44 metersy(960) = 2.44 + 15(1 - \cos(8\pi)) = 2.44 + 15(1 - 1) = 2.44 \text{ meters}

Final Positions

  • For B:

    • At t=1t = 1: (not matching options)
    • At t=4t = 4: (2.44 meters)
  • For E:

    • At t=4t = 4: (2.44 meters)
    • At t=16t = 16: (2.44 meters)

Conclusion

Brad's positions at the specified times do not match the given options directly based on the calculations. We need to check the rounding or other context-based adjustments.

If you want further clarification or additional calculations, please let me know! Here are some related questions to consider:

  1. How does the height of the Ferris wheel affect the calculation?
  2. What would the positions be if the wheel spun counterclockwise?
  3. How can you represent the positions on a graph?
  4. What adjustments would you make for a different diameter?
  5. How does the angular speed influence the overall experience of the ride?

Tip: Always double-check calculations to ensure accuracy, especially in applications involving periodic functions.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Circular Motion
Parametric Equations

Formulas

Angular speed: ω = θ/t
Vertical position: y(t) = h + r(1 - cos(θ(t)))
θ(t) = (π/120) * t

Theorems

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Suitable Grade Level

Grades 9-12