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To solve this problem, we can use the equations of motion under constant acceleration due to gravity. The height from which the phone is dropped is 300 meters, and we are asked to ignore air resistance.

The relevant equation for velocity when an object falls from a certain height is derived from the following kinematic equation:

\[
v^2 = u^2 + 2gh
\]

Where:
- \( v \) is the final velocity (what we are solving for),
- \( u \) is the initial velocity (which is 0 since the phone is dropped),
- \( g \) is the acceleration due to gravity (\( 9.8 \, \text{m/s}^2 \)),
- \( h \) is the height from which the object is dropped (300 meters).

Simplifying the equation for this case:

\[
v^2 = 0 + 2(9.8)(300)
\]
\[
v^2 = 5880
\]
\[
v = \sqrt{5880} \approx 76.68 \, \text{m/s}
\]

So, the phone will be traveling at approximately **76.68 m/s** when it hits the ground.

Would you like further details on how this was derived or have any additional questions?

Here are 5 related questions you might find interesting:
1. What is the effect of air resistance on the falling object?
2. How long will it take for the phone to hit the ground?
3. How would the final speed change if the object were dropped from twice the height?
4. How is terminal velocity different from the free-fall velocity we calculated here?
5. How can this calculation be applied to other planets with different gravitational forces?

**Tip:** Remember that gravitational acceleration is constant near Earth's surface, so objects fall with the same acceleration, regardless of their mass (ignoring air resistance).

Juan is standing on the top observation deck of the Eiffel Tower in Paris at a height of 300 meters. He drops his cell phone. How fast will the phone be traveling when it hits the ground? Ignore the effect of air resistance. Round to the nearest hundredth.

Learn how to calculate the speed of an object falling from the Eiffel Tower's observation deck using the kinematic equations of motion. This problem involves gravity, free fall, and calculating velocity using the formula v^2 = u^2 + 2gh, suitable for high school students.

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