Math Problem Statement

25a2 − 4b2 + 20ac +8bc factorise

Solution

To factorize the expression 25a24b2+20ac+8bc25a^2 - 4b^2 + 20ac + 8bc, we can follow these steps:

Step 1: Group terms in a strategic way

25a2+20ac4b2+8bc25a^2 + 20ac - 4b^2 + 8bc

Step 2: Factorize by grouping

Group the terms as follows: (25a2+20ac)(4b28bc)(25a^2 + 20ac) - (4b^2 - 8bc)

Step 3: Factorize each group

Factor out the common factors in each group: 5a(5a+4c)4b(b2c)5a(5a + 4c) - 4b(b - 2c)

Step 4: Combine using common binomial factor

Notice that (5a+4c)(5a + 4c) and (b2c)(b - 2c) are the factors. Thus, rewrite the expression as: (5a4b)(5a+4c)(5a - 4b)(5a + 4c)

Final Answer:

(5a4b)(5a+4c)(5a - 4b)(5a + 4c)

Would you like a step-by-step breakdown of any specific part? Here are 5 related questions for further exploration:

  1. How do you identify common factors in a polynomial?
  2. Can you explain the difference between grouping and substitution in factorization?
  3. How do you verify if a factorization is correct?
  4. What are some common strategies for factorizing four-term polynomials?
  5. How does recognizing patterns like the difference of squares help in factorization?

Tip: Always double-check your factorization by expanding the factors to see if you retrieve the original expression.

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Factorization
Difference of Squares

Formulas

Difference of Squares: a^2 - b^2 = (a - b)(a + b)
Factorization by Grouping

Theorems

Factorization Theorem

Suitable Grade Level

Grades 8-10