Math Problem Statement

x³ + y³ using sum and difference of two cubes

Solution

To factor the expression x3+y3x^3 + y^3 using the sum of two cubes, you can apply the following formula:

a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2)

For your expression x3+y3x^3 + y^3, substitute a=xa = x and b=yb = y into the formula:

x3+y3=(x+y)(x2xy+y2)x^3 + y^3 = (x + y)(x^2 - xy + y^2)

So, the factorization of x3+y3x^3 + y^3 is:

x3+y3=(x+y)(x2xy+y2)x^3 + y^3 = (x + y)(x^2 - xy + y^2)

Do you have any questions, or would you like further details?


Related Questions:

  1. How do you factor the difference of two cubes, x3y3x^3 - y^3?
  2. Can you explain why the formula for the sum of cubes works?
  3. What is the geometric interpretation of the sum of cubes?
  4. How can the sum of cubes be applied in solving algebraic equations?
  5. What is the relationship between the sum of cubes and the binomial theorem?

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Math Problem Analysis

Mathematical Concepts

Algebra
Cubic Equations

Formulas

Sum of cubes formula a^3 + b^3 = (a + b)(a^2 - ab + b^2)

Theorems

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Suitable Grade Level

Grades 9-12