Math Problem Statement

Factorise the following expressions: a) 3𝑥³ + 6𝑥² − 3𝑥 – 6

Solution

Let's factorize the given expression:

3x3+6x23x63x^3 + 6x^2 - 3x - 6

Step 1: Group the terms

We can group the terms to make factoring easier:

(3x3+6x2)(3x+6)(3x^3 + 6x^2) - (3x + 6)

Step 2: Factor out the greatest common factor (GCF) from each group

  • From the first group 3x3+6x23x^3 + 6x^2, the GCF is 3x23x^2.
  • From the second group 3x6-3x - 6, the GCF is 3-3.

Now, factor the GCF out from both groups:

3x2(x+2)3(x+2)3x^2(x + 2) - 3(x + 2)

Step 3: Factor out the common binomial factor

Now we can factor out the common factor (x+2)(x + 2):

(3x23)(x+2)(3x^2 - 3)(x + 2)

Step 4: Simplify further

Notice that 3x233x^2 - 3 has a common factor of 3:

3(x21)(x+2)3(x^2 - 1)(x + 2)

Finally, factor x21x^2 - 1 as a difference of squares:

3(x1)(x+1)(x+2)3(x - 1)(x + 1)(x + 2)

Final Answer:

3(x1)(x+1)(x+2)3(x - 1)(x + 1)(x + 2)

Would you like further details or have any questions?

Here are five related questions you might find interesting:

  1. How do you factor a cubic polynomial?
  2. What is the difference of squares method in factoring?
  3. Can all polynomials be factored by grouping?
  4. What are other methods of factoring polynomials?
  5. How does the greatest common factor help in simplifying expressions?

Tip: Always check for the greatest common factor first when factoring expressions—it simplifies the process!

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Factoring
Grouping
Difference of Squares

Formulas

ax^3 + bx^2 + cx + d = (px + q)(rx^2 + sx + t)
Difference of Squares: a^2 - b^2 = (a - b)(a + b)

Theorems

Factoring by Grouping
Greatest Common Factor
Difference of Squares

Suitable Grade Level

Grades 10-12