The problem shown in the image is asking to factor the trinomial $x^2 - 4x - 5$.

To factor this trinomial, we need to find two numbers that multiply to give the constant term (-5) and add to give the coefficient of the middle term (-4).

The numbers that satisfy these conditions are:

• Multiply to give -5
• Add to give -4

These numbers are -5 and +1.

So, we can factor the expression as: $x^2 - 4x - 5 = (x - 5)(x + 1)$

Thus, the factored form is: $(x - 5)(x + 1)$

Would you like more details on the factoring process or have any further questions?

Here are 5 related questions:

1. How do you factor trinomials when the leading coefficient is not 1?
2. What is the difference between factoring and expanding a quadratic?
3. How can you use the quadratic formula to verify factored trinomials?
4. How do you apply factoring in solving quadratic equations?
5. What happens if a trinomial cannot be factored?

Tip: Always check by multiplying your factors to see if they give you back the original trinomial.