https://file.aiquickdraw.com/mathbot/file/172607789995607pqp819.jpg

The problem shown in the image is asking to factor the trinomial \( x^2 - 4x - 5 \).

To factor this trinomial, we need to find two numbers that multiply to give the constant term (-5) and add to give the coefficient of the middle term (-4). 

The numbers that satisfy these conditions are:
- Multiply to give -5
- Add to give -4

These numbers are -5 and +1.

So, we can factor the expression as:
\[
x^2 - 4x - 5 = (x - 5)(x + 1)
\]

Thus, the factored form is:
\[
(x - 5)(x + 1)
\]

Would you like more details on the factoring process or have any further questions?

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Here are 5 related questions:
1. How do you factor trinomials when the leading coefficient is not 1?
2. What is the difference between factoring and expanding a quadratic?
3. How can you use the quadratic formula to verify factored trinomials?
4. How do you apply factoring in solving quadratic equations?
5. What happens if a trinomial cannot be factored?

**Tip**: Always check by multiplying your factors to see if they give you back the original trinomial.

Factor the quadratic trinomial: x^2 - 4x - 5

Learn how to factor the quadratic trinomial x^2 - 4x - 5. This problem covers key algebraic concepts and provides a step-by-step solution. Suitable for students in Grades 7-9.

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