You have presented three algebraic expressions:  
1. \( 6c + 5x \)  
2. \( 36^2 - 25x^2 \)  
3. \( 6c - 5x \)

Here's what we can do with them:

1. **Simplifying each expression**:
   - \( 6c + 5x \): This is already in its simplest form.
   - \( 36^2 - 25x^2 \): Here, we can simplify the square terms. \( 36^2 = 1296 \), so the expression becomes:
     \[
     1296 - 25x^2
     \]
     This is a difference of squares and can be factored as:
     \[
     (36 - 5x)(36 + 5x)
     \]
   - \( 6c - 5x \): This is already in its simplest form.

2. **Identifying patterns**:  
   Notice that the first and third expressions (\( 6c + 5x \) and \( 6c - 5x \)) resemble terms from the difference of squares formula, which states:
   \[
   (a + b)(a - b) = a^2 - b^2
   \]
   However, they do not directly fit the exact form as there is no square.

Would you like me to explore specific operations with these expressions (e.g., adding, multiplying)? If so, let me know! 

Here are some related questions:
1. How would you add \( 6c + 5x \) and \( 6c - 5x \)?
2. Can you factor the difference \( 1296 - 25x^2 \) further?
3. What happens when you multiply \( 6c + 5x \) by \( 6c - 5x \)?
4. How does the difference of squares formula apply to \( 36^2 - 25x^2 \)?
5. Can you simplify \( (6c + 5x)(6c - 5x) \)?

**Tip**: When dealing with squares or factorizations, always check if an expression fits the difference of squares pattern to simplify it easily.

Explore how to simplify and factor algebraic expressions like 6c + 5x, 36^2 - 25x^2, and 6c - 5x. This solution demonstrates the use of the difference of squares formula to factor expressions such as 36^2 - 25x^2 and provides insights into algebraic techniques for students in Grades 8-10.

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