The given expression is:

\[
x^2 + 6x + 9
\]

This is a quadratic expression. To factor it, we can recognize it as a perfect square trinomial. The general form of a perfect square trinomial is:

\[
a^2 + 2ab + b^2 = (a + b)^2
\]

Here, \(x^2 + 6x + 9\) can be rewritten as:

\[
(x + 3)^2
\]

Thus, the factored form is:

\[
(x + 3)^2
\]

Would you like further details or have any questions?

Here are 5 related questions for practice:

1. Factor \(x^2 - 4x + 4\).
2. Expand \( (x + 5)^2 \).
3. Solve the equation \(x^2 + 6x + 9 = 0\).
4. What is the vertex of the parabola \(y = x^2 + 6x + 9\)?
5. Find the roots of the equation \(x^2 + 6x + 8 = 0\).

**Tip:** Always check if a quadratic expression can be factored by looking for patterns like perfect square trinomials.

Learn how to factor the quadratic expression x^2 + 6x + 9 by recognizing it as a perfect square trinomial. This problem covers key algebraic concepts such as factoring quadratic expressions and identifying patterns in perfect square trinomials. Suitable for students in Grades 8-10.

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