Math Problem Statement
Factor the expression completely. (This type of expression arises in calculus when using the "Product Rule.") 5(x2 + 5)4(2x)(x − 3)4 + (x2 + 5)5(4)(x − 3)3
Solution
We are tasked with factoring the following expression completely:
Step 1: Identify Common Factors
First, we look for common factors in both terms:
-
In the first term :
- The factors are , , , and .
-
In the second term :
- The factors are , , and .
The common factors between the two terms are:
- (since the lower power is and it appears in both terms)
- (since the lower power is and it appears in both terms)
We can factor out these common terms:
Step 2: Factor out the remaining terms
After factoring out , we are left with:
Step 3: Simplify the remaining expression
Now, simplify the expression inside the brackets:
Start by distributing:
Now, add these two results:
Step 4: Final expression
The factored expression is:
Step 5: Optional Further Factoring
The quadratic term can be factored if possible. First, factor out a common factor of 2:
We check whether can be factored further. The discriminant is:
Since the discriminant is negative, the quadratic cannot be factored further using real numbers.
Final Factored Expression:
This is the completely factored form of the given expression.
Would you like more details or have any questions?
5 Related Questions:
- How do you apply the product rule in calculus?
- What are discriminants and how do they affect factoring?
- Can quadratic expressions with a negative discriminant be factored over the complex numbers?
- How do you recognize common factors in polynomial expressions?
- What are some examples of expressions that arise from applying the product rule?
Tip:
When factoring expressions with multiple terms, always check for common factors across all terms first before simplifying.
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Math Problem Analysis
Mathematical Concepts
Algebra
Factoring
Polynomial Expressions
Calculus
Formulas
(a^m)(a^n) = a^{m+n}
Distributive Property a(b + c) = ab + ac
Quadratic Formula: ax^2 + bx + c = 0
Theorems
Product Rule for Derivatives
Discriminant for Quadratic Equations
Suitable Grade Level
Grades 11-12, Calculus I
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