https://file.aiquickdraw.com/mathbot/file/1725878615400ag40v3tw.jpg

Let’s work through the factoring of each expression in the image:

### a. \( xy + 2x + y + 2 \)

We can factor this by grouping:

\[
(xy + 2x) + (y + 2) = x(y + 2) + 1(y + 2) = (x + 1)(y + 2)
\]

So, the factored form is:

\[
(x + 1)(y + 2)
\]

---

### b. \( x^3 + x^2 + x + 1 \)

We can use grouping again here:

\[
(x^3 + x^2) + (x + 1) = x^2(x + 1) + 1(x + 1) = (x^2 + 1)(x + 1)
\]

So, the factored form is:

\[
(x^2 + 1)(x + 1)
\]

---

### c. \( 2x^2 + 7x + 5 \)

We use the **AC method** for factoring quadratic expressions. Find two numbers that multiply to \(2 \times 5 = 10\) and add to \(7\), which are \(5\) and \(2\):

\[
2x^2 + 5x + 2x + 5 = (2x^2 + 5x) + (2x + 5)
\]

Factor each group:

\[
x(2x + 5) + 1(2x + 5) = (2x + 5)(x + 1)
\]

So, the factored form is:

\[
(2x + 5)(x + 1)
\]

---

### d. \( -5x^2 + x + 6 \)

First, factor out \(-1\):

\[
-(5x^2 - x - 6)
\]

Now, factor \(5x^2 - x - 6\). We need two numbers that multiply to \(5 \times (-6) = -30\) and add to \(-1\), which are \(5\) and \(-6\):

\[
5x^2 + 5x - 6x - 6 = (5x^2 + 5x) + (-6x - 6)
\]

Factor each group:

\[
5x(x + 1) - 6(x + 1) = (x + 1)(5x - 6)
\]

So, the factored form is:

\[
-(x + 1)(5x - 6)
\]

---

### e. \( x^4 + 3x^2 - 4x^2 - 12 \)

Combine like terms:

\[
x^4 - x^2 - 12
\]

Let \( y = x^2 \), so the expression becomes:

\[
y^2 - y - 12
\]

Factor this as a quadratic:

\[
(y - 4)(y + 3)
\]

Substitute back \( y = x^2 \):

\[
(x^2 - 4)(x^2 + 3)
\]

Factor further:

\[
(x - 2)(x + 2)(x^2 + 3)
\]

So, the factored form is:

\[
(x - 2)(x + 2)(x^2 + 3)
\]

---

### f. \( (3x + 2)^2 + 9x + 6 \)

Expand the square:

\[
(3x + 2)^2 = 9x^2 + 12x + 4
\]

So the expression becomes:

\[
9x^2 + 12x + 4 + 9x + 6 = 9x^2 + 21x + 10
\]

Factor using the AC method. We need two numbers that multiply to \(9 \times 10 = 90\) and add to \(21\), which are \(15\) and \(6\):

\[
9x^2 + 15x + 6x + 10 = (9x^2 + 15x) + (6x + 10)
\]

Factor each group:

\[
3x(3x + 5) + 2(3x + 5) = (3x + 5)(3x + 2)
\]

So, the factored form is:

\[
(3x + 5)(3x + 2)
\]

---

### g. \( x^2 - 5x + 6 \)

We need two numbers that multiply to \(6\) and add to \(-5\), which are \(-2\) and \(-3\):

\[
x^2 - 5x + 6 = (x - 2)(x - 3)
\]

So, the factored form is:

\[
(x - 2)(x - 3)
\]

---

Would you like more details or explanations on any of these solutions?

Here are five related questions you might find interesting:
1. How do you factor higher-degree polynomials using synthetic division?
2. What are the different methods to factor trinomials?
3. How do you use the difference of squares in factoring?
4. Can you explain how to factor by grouping in more detail?
5. How do you apply the quadratic formula to factor?

**Tip:** Always look for common factors first before using advanced factoring techniques like grouping or the quadratic method.

Factor the following completely: a. xy + 2x + y + 2 b. x^3 + x^2 + x + 1 c. 2x^2 + 7x + 5 d. -5x^2 + x + 6 e. x^4 + 3x^2 - 4x^2 - 12 f. (3x + 2)^2 + 9x + 6 g. x^2 - 5x + 6

Explore the step-by-step factoring of polynomial equations including linear, quadratic, and higher-degree expressions. Learn about factoring methods such as grouping, quadratic formulas, and difference of squares, suitable for Grades 8-10.

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