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In the given problem, you are tasked with finding two numbers that:

1. Multiply to give \(-70\) (the number on top).
2. Add up to \(-3\) (the number on the bottom).

We need to find two numbers that satisfy both conditions. Let's factor \(-70\) and then check which pair adds up to \(-3\).

The factors of \(-70\) are:
\[
(1, -70), (-1, 70), (2, -35), (-2, 35), (5, -14), (-5, 14), (7, -10), (-7, 10)
\]

Now, we look for a pair whose sum is \(-3\):
- \(7 + (-10) = -3\)

So, the two numbers are **7** and **-10**.

To summarize:
- \(7 \times (-10) = -70\) (satisfies the multiplication condition)
- \(7 + (-10) = -3\) (satisfies the addition condition)

The two numbers you're looking for are **7** and **-10**.

Would you like more details or have any questions? Here are 5 related questions:

1. How do you find the factors of a negative number systematically?
2. Can you apply this method to factor quadratics like \(x^2 - 3x - 70\)?
3. What if the top number was positive—how would that change the process?
4. What is the general rule for choosing signs in factor pairs?
5. How do we factor when the numbers are not integers?

**Tip**: Always check both the product and sum conditions when factoring using this method to ensure accuracy.

Write two numbers that multiply to the value on top (-70) and add to the value on bottom (-3).

Solve a factoring problem where two numbers multiply to -70 and add to -3. Learn the step-by-step process to find the solution, ideal for students in Grades 7-9. This problem reinforces key algebraic concepts and basic factoring principles.

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